To estimate the number of people in Springfield, population 10,000, who have a swimming pool in their backyard, 250 people were interviewed. Of those polled, 66 had a swimming pool. How many people in the city might one expect to have a swimming pool? (Round to the nearest whole number, if necessary.)
a. 2640 people
b. 37,879 people
c. 264 people
d. 2 people
Math Help - Multiple Choice Question?
You know that 66 out of 250 people had a swimming pool.
That allows you to form a probability.
P(pool) = 66/250 = 0.264
To find expected value, mutliply probability times sample size.
E(pool) = P(Pool)*n
E(pool) = 0.264*10,000
Reply:A. 10000 * (66/250) = 2640
Reply:A. 2640
26.4 %
Reply:Answer is A.
250 interviewed people is 100% 66 of them have a pool. So that is 66/2.5= 26.4 (2.5 is 1%). Then you can assume that 26.4% have a pool. So 10000 is 100 % 100=1% times 26.4 is 2640
Reply:Just set it up like this 66/250 = x/10000 cross multiply and you get 250x = 60,0000. then divide both sides by 250 and you get A = 2640 people
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